## Guest Book

**Teken gastenboek**

**Maryann**

**17 februari 2019 06:25 | Tummel Bridge**

Great looking website. Think you did a great deal of your own html coding.

**Delphia**

**17 februari 2019 03:16 | Sugar Land**

Many thanks really practical. Will certainly share website with my pals.

**Yolanda**

**17 februari 2019 02:32 | Altengrabow**

Great looking website. Presume you did a bunch of your very own coding.msg-106170http://ile-de-france.chambagri.fr/rep-forum/viewtopic.php?
f=7&t=5763http://foodstanlipal.forumcrea.com/viewtopic.php?pid=537

**Wilhemina**

**17 februari 2019 01:46 | Walperswil**

Howdy outstanding blog! Does running a blog similar to this take a lot of work?

I have virtually no understanding of computer programming but I was hoping to start my own blog soon. Anyway, should you have any recommendations or tips for new blog owners please share. I understand this is off topic nevertheless I just wanted to ask. Thank you!

I have virtually no understanding of computer programming but I was hoping to start my own blog soon. Anyway, should you have any recommendations or tips for new blog owners please share. I understand this is off topic nevertheless I just wanted to ask. Thank you!

**Jacquelyn**

**17 februari 2019 00:47 | Well Town**

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Exploring in Yahoo I at last stumbled upon this website. Reading this information So i am happy to show that I have a very excellent uncanny feeling I discovered just what I needed. I most indisputably will make certain to don't forget this website and give it a look on a continuing basis.

Exploring in Yahoo I at last stumbled upon this website. Reading this information So i am happy to show that I have a very excellent uncanny feeling I discovered just what I needed. I most indisputably will make certain to don't forget this website and give it a look on a continuing basis.

**Marie**

**17 februari 2019 00:43 | Certosa Di Trisulti**

Maintain the excellent work and generating the crowd!

**Ambrose**

**17 februari 2019 00:37 | Bastia**

(3^2x+3 - 28)(3^x-1 + 9) = 0? [3^(2x + 3) - 28].[3^(x - 1) + 9] = 0 The product of two factors is zero if one of these two factors is zero.

First case: [3^(2x + 3) - 28] = 0 3^(2x + 3) - 28 = 0 3^(2x + 3) = 28 Ln[3^(2x + 3)] = Ln(28) (2x + 3).Ln(3) = Ln(28) 2x + 3 = Ln(28) / Ln(3) 2x = [Ln(28) / Ln(3)] - 3 x = [Ln(28) / Ln(3)] - 3 / 2 x = [Ln(28) - 3.Ln(3)] / Ln(3) / 2 x = [Ln(28) - 3.Ln(3)] / 2.Ln(3) ?

you know that: Ln(28) = Ln(4 * 7) = Ln(4) + Ln(7) x = [Ln(4) + Ln(7) - 3.Ln(3)] / 2.Ln(3) ? you know that: Ln(4) = Ln[2^(2)] = 2.Ln(2) Or if you want it x = [Ln(28) - 3.Ln(3)] / 2.Ln(3) x = [Ln(28) - Ln(27)] / Ln(9) x = [Ln(28/27)] / Ln(9) x ? 0.01655163 Second case: [3^(x - 1) + 9] = 0 3^(x - 1) + 9 = 0 3^(x - 1) = - 9 ?

no possible because an exponential cannot be a negative value

First case: [3^(2x + 3) - 28] = 0 3^(2x + 3) - 28 = 0 3^(2x + 3) = 28 Ln[3^(2x + 3)] = Ln(28) (2x + 3).Ln(3) = Ln(28) 2x + 3 = Ln(28) / Ln(3) 2x = [Ln(28) / Ln(3)] - 3 x = [Ln(28) / Ln(3)] - 3 / 2 x = [Ln(28) - 3.Ln(3)] / Ln(3) / 2 x = [Ln(28) - 3.Ln(3)] / 2.Ln(3) ?

you know that: Ln(28) = Ln(4 * 7) = Ln(4) + Ln(7) x = [Ln(4) + Ln(7) - 3.Ln(3)] / 2.Ln(3) ? you know that: Ln(4) = Ln[2^(2)] = 2.Ln(2) Or if you want it x = [Ln(28) - 3.Ln(3)] / 2.Ln(3) x = [Ln(28) - Ln(27)] / Ln(9) x = [Ln(28/27)] / Ln(9) x ? 0.01655163 Second case: [3^(x - 1) + 9] = 0 3^(x - 1) + 9 = 0 3^(x - 1) = - 9 ?

no possible because an exponential cannot be a negative value

**Alejandra**

**16 februari 2019 23:48 | Gries**

Thanks really valuable. Will share website with my buddies.

**30044**

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